See Attachment for all 4 questions.Human Resource Consulting (HRC) is surveying a sample of 68 firms in order to study health care costs for a client. One of the items being tracked is the annual deductible that employees must pay. The state Bureau of Labor reports the mean of this distribution is $499 with a standard deviation of $80.(a)Compute the standard error of the sample mean for HRC. (Round your answer to 2 decimal places.) Standard error(b)What is the chance HRC finds a sample mean between $477 and $527? (Round z value to 2 decimal places and final answer to 4 decimal places.) Probability(c)Calculate the likelihood that the sample mean is between $492 and $512. (Round z value to 2 decimal places and final answer to 4 decimal places.) Probability(d)What is the probability the sample mean is greater than $550? (Round z value to 2 decimal places and final answer to 4 decimal places.) Probability
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